Question

In the given figure triangle ABC is circumscribed by a circle, AB =5 cm, $\angle A={30}^{\circ },\angle C={60}^{\circ }$. Find the length of side BC. $[sin{60}^{\circ }=0.86,sin{30}^{\circ }=0.5]$

Answer 1

In the given triangle ABC, applying sine rule we have

$\frac{AB}{sin{60}^{\circ }}=\frac{BC}{sin{30}^{\circ }}$

$\frac{5}{0.86}=\frac{BC}{0.5}$

$BC=\frac{5\times 0.5}{0.86}=2.9cm$