You visited us 1 times! Enjoying our articles? Unlock Full Access!

Angles in Alternate Segments

In the given ...

Question

$I n t h e g i v e n f i g u r e, △ A B C i s i n s c r i b e d i n a c i r c l e . T h e b i s e c t o r o f ∠ B A C m e e t s B C a t D a n d t h e c i r c l e a t E, i f E C i s j o i n e d t h e n ∠ E C D = 30^{0} . F i n d ∠ B A C .$

30°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60°

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70°

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
60°

$∵$ Angles in same segment are equal

$∠$ BCE = $∠$ BAE = $30^{\circ}$

$∵$ AD is a bisector

So $∠$ BAE = $∠$ CAE = $30^{\circ}$

$∴$ $∠$ BAC = $30^{\circ}$ + $30^{\circ}$ = $60^{\circ}$

Suggest Corrections

Similar questions

△ A B C

∠ B A C

∠ E C D

= 30^{o}

∠ B A C

Δ A B C

∠ B A C

∠ E C D = 30^{o}

∠ B A C

△

∠

∠

^{o}

∠

△ A B C

∠ A

∠ E C D = 30^{\circ}

∠ A

Join BYJU'S Learning Program