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Question

In the given figure, DA and CAB are on the same base AB. Prove that DABCAB
616616_7cf8bccd7ab7406286356193fd9e24e0.PNG

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Solution

Consider DAB and CAB
DAB=35o+20o=55o=CBA (given)
DBA=CAB=20o
AB is common to both the triangles.
DBACAB (by ASA axiom)

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