Question

In the given figure, two parallel lines l and m are cut by two transversals n and p. Find the values of x and y.

[3 marks]

Answer 1

Solution:
Since lines l and m are parallel and p is transversal.
Therefore, $x+{66}^{\circ }={180}^{\circ }\left[\text{co-interior angles}\right]\Rightarrow x={180}^{\circ }-{66}^{\circ }\Rightarrow x={114}^{\circ }\text{(1.5 marks)}$
Again, lines l, m are parallel and n is transversal.
Therefore, $y+{48}^{\circ }={180}^{\circ }\left[\text{co-interior angles}\right]\Rightarrow y={180}^{\circ }-{48}^{\circ }\Rightarrow y={132}^{\circ }\text{(1.5 marks)}$