In the given figure VB is (All surfaces are smooth and string is massless and inextensible)
A
2m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D10m/s For an inextensible string velocity component of the end points along the string should be same otherwise it will break.
So, taking the component of VB along the string, we have:
Component along the string=VBcos37∘
And, this velocity should be equal to VA ⇒VA=VBcos37∘⇒VB=VAcos37∘=845=10m/s∵cos37∘=45