You visited us 1 times! Enjoying our articles? Unlock Full Access!

The Mid-Point Theorem

In the given ...

Question

In the given figure, we have $A B = B C, B X = B Y$ . Then:

A X = C Y

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B Y = C Y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B X = C Y

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B X = A X

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $A X = C Y$
Since $A B = B C$
$∴ A X + B X = B Y + C Y$
Since $B X = B Y$
$∴ A X + B X - B X = B Y + C Y - B Y$
$\Rightarrow A X = C Y$

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ \begin{matrix} a & b & a x + b y b & c & b x + c y a x + b y & b x + c y & 0 \end{matrix} ∣ ∣ ∣ ∣

a x + b y + c x + b x + c y + a y

△ A B C, X Y ∥ B C, \frac{A Y}{C Y} = \frac{1}{2}

A X = 4

B X

X Y | | B C

A X = p - 3

B X = 2 p - 2

\frac{A Y}{C Y} = \frac{1}{4}

p

u =

a x

+

b y

+

v =

a y

+

b z

+

c x

w = a z + b x +

c y

∣ ∣ ∣ ∣ \begin{matrix} a & b & c b & c & a c & a & b \end{matrix} ∣ ∣ ∣ ∣ . ∣ ∣ ∣ ∣ \begin{matrix} x & y & z y & z & x z & x & y \end{matrix} ∣ ∣ ∣ ∣

Join BYJU'S Learning Program