In the given figure, we have $A C ⊥ C D, B C ⊥ C D and D A = D B .$ then $C A = C B$ .

True

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False

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Solution

The correct option is A True
In $△ A C D, △ B C D$
$D A = D B$
$∠ A C D = ∠ B C D = 90^{\circ}$
$C D = C D$ $(∵ common side)$
By $S A S$ congruency
$△ A C D ≅ △ B C D$
So $C A = C B$
So the given relation is $True$

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