In the given figure, which congruence rule can be used to prove that $△$ ABC $≅$ $△$ CDA?

(2 Marks)

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Solution

In $△ A B C$ and $△ C D A$ ,
AC = CA (common side)
AB = CD (given) (1 Mark)
Also, $∠ A C B$ = $∠ C A D$ = $90^{\circ}$ (from the figure)
Therefore, $△ A B C ≅ △$ CDA (by RHS congruence condition) (1 Mark)

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