Question

In the given figures, lines $AB$ and $CD$ intersect at point $O$ such that $\angle AOD+\angle BOD+\angle BOC={300}^{\circ }$. Find $\angle AOC$

Answer 1

we know that $\underset{}{\angle AOD+\angle BOD+\angle BOC}+\angle AOC={360}^o$

Given $={300}^o$

$\Rightarrow {300}^o+\angle AOC={360}^o$

$\Rightarrow \angle AOC={60}^o$