if the lines are parallel
x+900=1800 are co-interior angles
x=1800−900=900
∠2=x
∠2=900
We know that the sum of angles of a triangle
∠1+∠2+300=1800
Substituting the values
∠1+900+300=1800
By further calculation
∠1+1200=1800
∠1=180−120=600
Here ∠1=k are vertically opposite angles
k=600
here ∠1=z are alternate angles
z=600
Here k+y=1800 are co-interior angles
Substituting the values
600+y=1800
y=180−60=1200
Therefore x=900,y=1200,z=600,k=600.