wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the given image, segment AB has been divided in the ratio 3:2. This is done by
1. Draw any ray AX making acute angle with AB.
2. Draw a ray BY parallel to AX by making ABY=BAX
3. Locate the points A1,A2,A3...A3 on AX and B1,B2 on BY such that AA1=A1A2=BB1=B1B2
4. Join A3B2by using which of the properties of parallel lines?

A
Corresponding angle are equal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Alternate interior angles are equal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Co-interior angle are supplementary
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Perpendicular bisector theorem
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Alternate interior angles are equal

Here we use alternate interior angles are equal then the lin4es are parallel and XAB=ABY as AX parallel to BY.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Dividing a Line Segment
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon