Question

In the given, lewis structure of $S_2{O}_3^{2-}$ formal charge present on sulphur atoms $1$ and $2$ respectively are:

• A. $zero,+1$
• B. $+1,+1$
• C. $+2,+2$
• D. $zero,zero$

Answer 1

Answer: (D)

$zero,zero$

Formal charge is expressed as (a lewis dot structure)

$=$ (total no. of valence electron in free atom) $-$ (total no. of non bonding electron) $-\frac{1}{2}$ (total no. of bonding electron)

$=V-L-\frac{1}{2}\times S$

$L=$ lone pair electrons, $S=$ bonding electrons

For Sulphur atom $\left(1\right)$

$FC=6-4-\frac{1}{2}\times 4\Rightarrow 6-4-2\Rightarrow 0$

For Sulphur atom $\left(2\right)$

$FC=6-0-\frac{1}{2}\times 12\Rightarrow 6-6=0$

Ans is $\left(D\right)$.