In the given mirror

C – The center of the sphere to which the mirror is part of

F – The focus of the mirror

P – Pole of mirror

A – Point on the mirror

D – The point on the principal axis.

If a ray of light starts from C and is incident on A from which point will the reflected ray pass through:

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Solution

The correct option is B
C

CA will fall normally to the concave mirror so by laws of reflection the angle of incidence is $0^{\circ}$ and so the angle of reflection will be $0^{\circ}$ . Hence the ray will retrace its path and pass through C (center of curvature).

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Similar questions

In the given mirror

C – centre of the sphere to which the mirror is part of

F – focus of the mirror

P – pole of the mirror

A – point on the mirror

D – point on the principal axis.

If a ray of light starts from C and is incident on A from which point will the reflected ray pass through?

In the given mirror

C - centre of the sphere to which the mirror is part of

F - focus of the mirror

P - pole of mirror

A - point on mirror

D - point on principal axis.

If a ray of light starts from C and is incident on A from which point will the reflected ray pass through

In the given mirror:
C – the centre of the sphere to which the mirror is part of
F – the focus of the mirror
P – pole of the mirror
A – a point on the mirror
D – a point on the principal axis.
If a ray of light starts from C and is incident on the mirror at the point of incidence A, then the reflected ray will pass through which point?

Q. A ray parallel to the principal axis is incident on a concave mirror. After reflection which point corresponding to the mirror the ray should pass through ?

Q. A light ray passing through the focus is incident on a concave mirror. It is reflected parallel to the principal axis.

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The correct option is B C CA will fall normally to the concave mirror so by laws of reflection the angle of incidence is 0∘ and so the angle of reflection will be 0∘. Hence the ray will retrace its path and pass through C (center of curvature).

The correct option is B
C

CA will fall normally to the concave mirror so by laws of reflection the angle of incidence is $0^{\circ}$ and so the angle of reflection will be $0^{\circ}$ . Hence the ray will retrace its path and pass through C (center of curvature).