In the given nuclear reaction
$_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C + X$
$X$ represents

Neutron

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Proton

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Positron

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Electron

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Solution

The correct option is A Neutron
Balancing atomic number and mass number on both sides $_{0}^{1} n$ (neutron).

Therefore, the term X represents the neutron.

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_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C + X

_{4}^{9} B e +_{2}^{4} H e ⟶_{6}^{12} C +_{0}^{1} n

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_{4} B e^{9} +_{2} H e^{4} \to_{6} c^{12}

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