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Question
In the given parallelogram ABCD, DP = BQ and ∠ADP = ∠CBQ. Which triangle is congruent to ΔADP?
In the given parallelogram ABCD, DP = BQ and ∠ADP = ∠CBQ. Which triangle is congruent to ΔADP?
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Solution
The correct option is A ΔCBQ
In ΔADP and ΔCBQ,
∠ADP = ∠CBQ (given)
AD = BC (since the opposite sides of a parallelogram are equal)
DP = QB (given)
Hence, by S.A.S, ΔADP ≅ ΔCBQ.
In ΔADP and ΔCBQ,∠ADP = ∠CBQ (given)
AD = BC (since the opposite sides of a parallelogram are equal)
DP = QB (given)
Hence, by S.A.S, ΔADP ≅ ΔCBQ.