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Question

In the given parallelogram ABCD, DP = BQ and ADP=CBQ. To which triangle is ΔADP congruent to?



A

ΔCBQ

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B

ΔPDQ

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C

ΔQBC

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D

ΔPQB

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Solution

The correct option is A

ΔCBQ


In ΔADP and ΔCBQ
ADP=CBQ (given)
AD = BC (opp. sides of parallelogram)
DP = QB (given)
ΔADPΔCBQ (by S.A.S. rule)


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