Question

In the given problem, solve and graph. Express answers in both inequality and interval notaion.$x^2<3x-3$

Answer 1

$x^2<3x-3$

$x^2-3x+3<0$

${(x-\frac{3}{2})}^2+\frac{3}{4}<0$

${(x-\frac{3}{2})}^2<-\frac{3}{4}$

$NoSolutionforx\in R$