In the given quadrilateral, QS is the bisector of ∠S and ∠Q. PS=5 cm and PQ=8 cm. Fin the measure of SR.
QS is the bisector of ∠S and ∠Q.
PS=5 cm
In ΔPSQ and ΔRSQ
∠PSQ=∠RSQ [Since, QS is the bisector of ∠S.]
SQ=SQ [Since, common side of ΔPSQ and ΔRSQ]
∠PQS=∠RQS [Since, QS is the bisector of ∠Q.]
By, A.S.A congruence criterion,
ΔPSQ≅ΔRSQ
By CPCT,
SR=SP=PS=5 cm
Hence, Option A is correct.