In the given question, fill in the blanks to make the statement true.
The sum of a two-digit number and the number obtained by reversing the digits is always divisible by ___.
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Solution
11 Let ab be any two-digit number, then the number obtained by reversing its digits is be. Now, ab + ba = (10a + b) + (10b + a) = 11a + 11b = 11(a + b) Hence, ab + ba is always divisible by 11 and (a + b).