In the given question, out of four options, only one is correct. Write the correct answer.
If x + y + z = 6 and z is an odd digit, then the three- digit number xyz is (a) an odd multiple of 3 (b) an odd multiple of 6 (c) an even multiple of 3 (d) an even multiple of 9
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Solution
We have, x + y + z = 6 and z is an odd digit. Since sum of the digits is divisible by 6, it will also be divisible by 2 and 3 but the unit digit is odd, so it is divisible by 3 only. Hence, the number is an odd multiple of 3.