The correct option is
B Statement I and II both are needed.
(C): Try to determine the value of x using the LCM of x and certain other integers.
(1) INSUFFICIENT:
Statement (1) tells you that x and 45(3×3×5) have an LCM of 225(=3×3×5×5=32×52).
Notice on the chart to the right that the LCM of x and 45 contains two 3's. Because 45 contains two 3's, x can contain zero, one, or two 3's. The LCM of x and 45 contains two 5's. Because 45 contains only ONE 5, x must contain exactly two 5's. (If x contained more 5's, the LCM would contain more 5's. If x contained fewer 5's, the LCM would contain fewer 5's.)
Number 3 5
x ? × ?
45 32 × 51
LCM 32 × 52
Therefore, x can be any of the following numbers:
x=5×5=25
x=3×5×5=75
x=3×3×5×5=225
(2) INSUFFICIENT:
Statement (2) tells you that x and 20(2×2×5) have an LCM of 300(=2×2×3×5×5=222×31×52).
The LCM of x and 20 contains two 2's. Because 20 contains two 2's, x can contain zero, one, or two 2's. The LCM of x and 20 contains one 3. Because 20 contains no 3's, x must contain exactly one 3.
Number 2 3 5
x ? × ? × ?
20 22 - × 51
LCM 22 × 31 × 52
Further more, the LCM of x and 20 contains two 5's. Because 20 contains one 5, x must contain exactly two 5's.
Therefore, x can be any of the following numbers:
x=3×5×5=75.
x=2×3×5×5=150.
x=2×2×3×5×5=300.
(1) AND (2) SUFFICIENT:
Statement (1) tells you that x could be 25, 75, or 225. Statement (2) tells you that x could be 75, 150, or 300. The only number that satisfies both of these conditions is x = 75. Therefore, you know that x must be 75. The correct answer is (C).