In the given reaction CH3−CH2−COOH(i)AgNO3−−−−−−→(ii)Br2/Δ[X], [X] will be :
A
ethyl bromide
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B
propyl bromide
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C
propyl propanoate
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D
all of the above
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Solution
The correct option is A ethyl bromide The treatment of propionic acid with silver nitrate forms silver salt of propioinc acid. The treatment with bromine results in replacement of alpha hydrogen atom with bromine. Heating results in decarboxylation. Hence, the end product is ethyl bromide (compound X). CH3−CH2−COOH(i)AgNO3−−−−−−→(ii)Br2/ΔCH3−CH2−Br[X]