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Question

In the given reaction CH3−CH2−COOH(i)AgNO3−−−−−−→(ii)Br2/Δ[X], [X] will be :

A
ethyl bromide
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B
propyl bromide
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C
propyl propanoate
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D
all of the above
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Solution

The correct option is A ethyl bromide
The treatment of propionic acid with silver nitrate forms silver salt of propioinc acid.
The treatment with bromine results in replacement of alpha hydrogen atom with bromine.
Heating results in decarboxylation.
Hence, the end product is ethyl bromide (compound X).
CH3CH2COOH(i)AgNO3−−−−−(ii)Br2/ΔCH3CH2Br[X]

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