Question

In the given reaction sequence :
$C{H}_3-C{H}_2-OH\underset{\left(ii\right)H^{\oplus }}{\overset{\left(i\right)KMn{O}_4/O^{\Theta }H/\Delta }{\to }}\left(A\right)\underset{\left(ii\right)N{H}_3/\Delta }{\overset{\left(i\right)SOC{l}_2}{\to }}\stackrel{B{r}_2/KOH}{\to }\left(C\right)$
$\left(C\right)$ will be :

• A. Methylamine
• B. Eltylamine
• C. Propylamine
• D. Acetamide

Answer 1

The correct option is A Methylamine

Ethanol is oxidized with potassium permanganate in alkaline medium followed by acidification to obtain acetic acid (compound A). The carboxylic group is converted to acid chloride by thionyl chloride. This followed by reaction with ammonia to form acetamide. Hoffmann bromide degradation gives methylamine (compound C).
$C{H}_3-C{H}_2-OH\underset{\left(ii\right)H^{\oplus }}{\overset{\left(i\right)KMn{O}_4/O^{\Theta }H/\Delta }{\to }}\underset{\left(A\right)}{C{H}_3-COOH}\underset{\left(ii\right)N{H}_3/\Delta }{\overset{\left(i\right)SOC{l}_2}{\to }}C{H}_3-CON{H}_2\stackrel{B{r}_2/KOH}{\to }\underset{\left(C\right)}{C{H}_{3}N{H}_2}$