In the given reaction, the product formed A and B are :
$3 C H_{3} - C H_{2} - O H + P C l_{3} \to A + B$

3 C_{2} H_{5} - C l + H_{2} O

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3 C_{2} H_{5} - C l + H C l

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3 C_{2} H_{5} - C l + H_{3} P O_{3}

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3 C_{2} H_{5} - C l + P O C l_{3}

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Solution

The correct option is D $3 C_{2} H_{5} - C l + H_{3} P O_{3}$
The products formed are $3 C_{2} H_{5} - C l + H_{3} P O_{3}$ when $3 C H_{3} - C H_{2} - O H$ is reacted with $P C l_{3}$ .

$3 C H_{3} - C H_{2} - O H + P C l_{3} \to 3 C_{2} H_{5} - C l + H_{3} P O_{3}$
Hence option C is correct.

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Similar questions

3 C H_{3} - C H_{2} - O H + A \to 3 C_{2} H_{5} - C l + H_{3} P O_{3}

3 C H_{3} - C H_{2} - O H + P C l_{3} \to 3 C_{2} H_{5} - C l + A

C H_{3} - C H_{2} - O H + C O C l_{2} - ---- \to P y r i d e n e C H_{2} - C H_{2} - C l + X + H C l

3 C H_{3} - C H_{2} - O H + P C l_{3} - --- \to C H_{3} - C H_{2} - C l + Y

X & Y

R O H + X \to R - C l + S O_{2} + H C l

R O H + Y \to R - C l + P O C l_{3} + H C l

R O H + Z \to R - C l + H_{3} P O_{3}

3 R - O H + P C l_{3} \to 3 R - C l + H_{3} P O_{3}

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