In the given reaction,
(X) will be:

(N H_{4})_{2} S_{x}

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H_{2} S / O H

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Z n / H C I

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N a H S O_{3} / C H_{3} O H

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Solution

The correct option is A $(N H_{4})_{2} S_{x}$

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Similar questions

Balance the following equations :

(a) $N_{2} + H_{2} \to N H_{3}$

(b) $H_{2} + O_{2} \to H_{2} O$

(d) $C O + O_{2} \to C O_{2}$

(e) $Z n + H C I \to Z n C l_{2} + H_{2}$

C H_{3} B r + O H^{-} \to C H_{3} O H + B r^{-}

Arrange in decreasing order of basicity,

$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

C O + H_{2} \to C H_{3} O H

C H_{3} B r + O H^{-} C_{2} H_{5} O H - ---- \to C H_{3} O H + B r^{-}

C H_{3} B r + O H^{-} (C H_{3})_{2} S O - ----- \to C H_{3} O H + B r^{-}

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