Question

In the given reactions, the rate of reaction of $\left(I\right)$ is faster than that of $\left(II\right)$. By which mechanism do both reactions proceed?

• A. E1
• B. E2
• C. E1cB
• D. $\alpha$-Elimination

Answer 1

The correct option is B E2

Since, the rates of two reactions are different, the breaking of C-H and C-D bonds are involved in the slow step (or rate determining effect).

This indicates $E_2$ mechanism in which the rate determining step involves cleavage of C-H (or C-D) and C-Br bond.

Option B is correct.