Question

In the given right angle triangle ABC, if = ${30}^{\circ }$ and then the sides AB and BC would be………………………………………cm

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Answer 1

$\cos$ $\theta$ =$\frac{\sqrt{3}}{2}$ at $\theta$=${30}^{\circ }$

So, $\frac{AB}{AC}$=$\frac{\sqrt{3}}{2}$

AB= 5$\sqrt{3}$cm

AB=$\frac{\sqrt{3}AC}{2}$

AB=5$\sqrt{3}$cm

And $\sin$ $\theta$ =$\frac{1}{2}$ at =${30}^{\circ }$

So, $\frac{BC}{AC}$=$\frac{1}{2}$

BC=$\frac{10}{2}$

BC=5cm