Question

In the given right angle triangle, if $Sin\theta =\frac{3}{5}$, then find the value of $3tan\alpha$.

• A. 3
• B. 5
• C. 4
• D. 1

Answer 1

The correct option is C

4

In the given figure.Given,
$sin\theta =\frac{3}{5}=\frac{AB}{AC}$
${AC}^2={AB}^2+{BC}^2$
$5^2=3^2+{BC}^2$
BC = 4

Hence,
$3tan\alpha =3\times \frac{BC}{AB}=\frac{4}{3}$
$3tan\alpha$ = 4