In triangle ABC, ∠ABC=90o. AB=BC(Since, ABC is an isosceles triangle)
So, θ=α=45o
cosθ=1√2
ABAC=1√2
AB=AC√2
AB=5√2 cm
And, sinθ=1√2
BCAC=1√2
BC=5√2 cm
Area of triangle=12(Base×Height)=12(5√2×5√2)=25 cm2
In the given right angled isosceles triangle ABC, if AC=10 cm then the area of triangle is ___ cm2
In the given right angled isosceles triangle ABC, if AC = 10 cm then the area of triangle (in cm2) is ___.