In the given right-angled triangle, if AB = 3 cm, BC = 4 cm, then the value of AC (in cm) is
By Pythagoras theorem we know that
AC2= AB2+BC2
So, AC2= 42 + 32 = 16 + 9 = 25
So, AC = 5
In a right angled triangle, if AB=3 cm, BC=4 cm then what is the value of cos A?