Question

In the given $S_{N}2$ reaction, _______will get substituted.

• A. bromide
• B. iodide
• C. $BrC{H}_2{O}^{-}$
• D. $I{\left(C{H}_2\right)}_3{O}^{-}$

Answer 1

Answer: (A)

bromide

Allyl compounds react rapidly by the $S_{N}2$ mechanism because the π system of the adjacent double bond can stabilize the transition state by conjugation.