In the given sequence of reaction, the final product will be:
$C H_{2} = C H - C H_{2} C H_{3} H B r / H_{2} O - ----- \to A C_{2} H_{5} O N a - ----- \to B$

C H_{3} - O - C_{2} H_{5}

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C H_{3} - (C H_{2})_{3} - O - C_{2} H_{5}

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(C H_{3})_{2} C H - O - C H (C H_{3})_{2}

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C H_{3} C H (O C H_{2} C H_{3}) - C H_{2} C H_{3}

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Solution

The correct option is B $C H_{3} C H (O C H_{2} C H_{3}) - C H_{2} C H_{3}$
The sequence of the reactions is as shown.
$C H_{2} = C H - C H_{2} C H_{3} H B r / H_{2} O - ----- \to C H_{3} C H (B r) - C H_{2} C H_{3} A C_{2} H_{5} O N a - ----- \to C H_{3} C H (O C H_{2} C H_{3}) - C H_{2} C H_{3} B$
In the first step, a molecule of $H B r$ is added to $C = C$ double bond. Bromine atom is added to more substituted $C$ atom and $H$ atom is added to less substituted $C$ atom. Second step is williamson synthesis in which sodium alkoxide reacts with alkyl halide to form an ether.

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Similar questions

\begin{matrix} C H_{3} - & C H & - C H_{2} - O - C_{2} H_{5} + H I △ - \to ? | C H_{3} \end{matrix}

The $C - O - C$ angle would be maximum in

C H_{3} - O | | C - C H_{2} - O | | C - O - C_{2} H_{3}

C H_{3} - O H | C = C H - O | | C - O - C_{2} H_{5}

[X]

C H_{3} - C H | C H_{3} - O | | C - C H_{2} - C H_{3} C F_{3} C O O O H - ------- \to [X]

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

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