Question

In the given series

$1,8,3,5,1,3,7,8,1,5,7,3,5,8,3,1,5,3,7,1,8,3,5,3,7,8,3,5,1,7,3,7,$

$5,1,8,3,1,7,1,8,3,8,5,1$

How many times the two consecutive numbers (i.e. numbers one after the other) are such that the first is $4$ more than the second?

• A. $6$
• B. $9$
• C. $11$
• D. $13$

Answer 1

The correct option is A $6$

$1,8,3,(5,1),3,7,8,1,5,(7,3),5,8,3,1,5,3,7,1,8,3,5,3,7,8,3,(5,1),(7,3),7,$

$(5,1),8,3,1,7,1,8,3,8,(5,1)$

There are $6$ pairs in which difference of $4$ is there.