Question

In the given set of aromatic compounds, the correct order of reactivity toward Friedel-Crafts alkylation is:

• A. i > ii > iii > iv
• B. ii > iv > iii > i
• C. iv > ii > iii > i
• D. iii > i > iv > ii

Answer 1

The correct option is C iv > ii > iii > i

The correct order of reactivity toward Friedel-Crafts alkylation is $iv>ii>iii>i$
Friedel-Crafts alkylation is electrophilic aromatic substitution reaction.
In $iv$, the electron releasing $methoxy$ group increases the electron density on $benzene$ ring and increases the reactivity toward Friedel-Crafts alkylation.
In $i$, the electron withdrawing $nitro$ group decreases the electron density on $benzene$ ring and decreases the reactivity toward Friedel-Crafts alkylation.

Hence, option (C) is the correct answer.