Let’s solve each row one by one.
The product of the numbers in row \(1\) is \(120.\)
So, the product of the numbers in each row should be \(120.\)
For row \(2\) and row \(3\), we divide \(120\) by the product of the known numbers in the respective rows to get the unknown numbers. This is because multiplication is the inverse of division.
For row 2:
\(5 \times A \times 2 = 120\)
\(10 \times A = 120\)
Therefore, \(A = 120\div10=12\)
It means, we need to multiply \(10\) by \(12\) to get \(120\).
For row 3:
\(2 \times 15 \times B = 120\)
\(30 \times B = 120\)
Therefore, \(B = 120\div30=4\)
It means, we need to multiply \(30\) by \(4\) to get \(120. \)
Therefore, \(A = 12\) and \(B = 4.\)