In the given transistor circuit, the base current is 35μA. The value of Rb is -
A
100kΩ
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B
200kΩ
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C
300kΩ
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D
400kΩ
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Solution
The correct option is B200kΩ As the emittter base junction is reverse biased, the voltage drop across it will be zero. ⇒7−IbRb=0 IbRb=7 Rb=735×10−6=2×105=200kΩ