Question

In the given trapezium ABCD, AB = 5 cm, CE=DF = 3 cm, if BE = 4 cm, find the area of given trapezium.

• A. 12 $c{m}^2$
• B. 15 $c{m}^2$
• C. 32 $c{m}^2$
• D. 35 $c{m}^2$

Answer 1

Answer: (C)

32 $c{m}^2$

Area of trapezium ABCD
= $\frac{1}{2}$$\times$(Sum of parallel sides)$\times$height
= $\frac{1}{2}$$\times$(AB+DF+FE+CE)$\times$BE
= $\frac{1}{2}$$\times$2$\times$(AB+DF)$\times$BE
.....(As AB=FE, CE=DF)
= (AB+DF)$\times$BE = (5+3)$\times$4 = 8$\times$4 = 32 $c{m}^2$