ABC - - A -50- - c -50- AB -10 cm- then BC is equal to -sin 60-0-86- sin 50-0-76-A- 12-8 cmB- 11-31 cmC- 13-4 cmD- 14-8 cm

The correct option is B 11.31 cm In the given triangle applying sine rule we have BC/sin 60^∘=AB/sin 50^∘ BC/0.86=10/0.76 BC = 8.6 × 10/0.76 BC = 11.31 cm ...

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Standard X

Mathematics

Sine Rule

ABC , ∠ A =50...

Question

In the given triangle $A B C, ∠ A = 50^{\circ}, ∠ c = 50^{\circ}$ , AB =10 cm, then BC is equal to $[s i n 60^{\circ} = 0.86, s i n 50^{\circ} = 0.76]$

12.8 cm

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11.31 cm

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13.4 cm

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14.8 cm

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Solution

The correct option is B
11.31 cm

In the given triangle applying sine rule we have

$\frac{B C}{s i n 60^{\circ}} = \frac{A B}{s i n 50^{\circ}}$

$\frac{B C}{0.86} = \frac{10}{0.76}$

BC = $\frac{8.6 \times 10}{0.76}$

BC = 11.31 cm

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In the given triangle $A B C, ∠ A = 50^{\circ}, ∠ c = 50^{\circ}$ , AB =10 cm, then find the length of BC. $[s i n 60^{\circ} = 0.86, s i n 50^{\circ} = 0.76]$

In Triangle $A B C, A B = 15 c m, A C = 8 c m, ∠ A = 50^{\circ},$ as shown below. Find the length of BC. $[s i n 50^{\circ} = 0.76, c o s 50^{\circ} = 0.64]$

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Q. In triangle

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In the given triangle ABC,∠A=50∘,∠c=50∘, AB =10 cm, then BC is equal to [sin 60∘=0.86,sin 50∘=0.76]

The correct option is B 11.31 cm In the given triangle applying sine rule we have BCsin 60∘=ABsin 50∘ BC0.86=100.76 BC = 8.6×100.76 BC = 11.31 cm

In the given triangle $A B C, ∠ A = 50^{\circ}, ∠ c = 50^{\circ}$ , AB =10 cm, then BC is equal to $[s i n 60^{\circ} = 0.86, s i n 50^{\circ} = 0.76]$

The correct option is B
11.31 cm

In the given triangle applying sine rule we have

$\frac{B C}{s i n 60^{\circ}} = \frac{A B}{s i n 50^{\circ}}$

$\frac{B C}{0.86} = \frac{10}{0.76}$

BC = $\frac{8.6 \times 10}{0.76}$

BC = 11.31 cm