In the given triangle ABC, the point P is the intersection of all the medians. The length of AP is 10 cm. Then what is the length of PE?

2 cm

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5 cm

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20 cm

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15 cm

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Solution

The correct option is B
5 cm

The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1.
So, AP : PE =2 : 1
Here, AP=10 cm

So, $P E = \frac{A P}{2} = 5 c m$

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In the given triangle ABC, the point P is the intersection of all the medians. The length of AP is 10 cm. Then what is the length of PE?

The correct option is B 5 cm The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1. So, AP : PE =2 : 1 Here, AP=10 cm So, PE = AP2 = 5 cm

The correct option is B
5 cm

The point of intersection of all the medians is called the centroid and it divides each median is in the ratio of 2 : 1.
So, AP : PE =2 : 1
Here, AP=10 cm

So, $P E = \frac{A P}{2} = 5 c m$