In ΔABC,AC= BCSo, angles opposite to equal sides will be equal too.⇒∠ABC = ∠BAC⇒∠ABC = ∠BAC= x Opposite angles are equal.so, ∠ACB = 92°The sum of angles of a triangle is 180°so, ∠ABC + ∠BAC +∠ACB = 180°⇒x + x + 92° = 180°⇒ 2x = 180° − 92°⇒2x = 88°⇒x = 44°Now, y=x=44° (∵AC=BC)