Question

In the given triangle find sec 60 , if $\frac{AC}{BC}$ = 2

• A. 1/2
• B. 2/√3
• C. 2
• D. √3

Answer 1

The correct option is C

2

In $△ABC$, $\angle C$ = 180 - $\angle A+\angle B$ = ${60}^{\circ }$

sec 60 = sec C = $\frac{AC}{BC}$ = 2