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Apollonius's Theorem

In the given ...

Question

In the given triangle , which of the following is true ?

PQ² + PR² = QR²

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PR² + QR² = PQ²

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PQ² + QR² = PR²

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All of these

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Solution

The correct option is C
PQ² + QR² = PR²

${P Q}^{2}$ + ${Q R}^{2}$ = ${P R}^{2}$ . This is the Pythagoras theorem.

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Similar questions

{P R}^{2} + {P Q}^{2} = {Q R}^{2}

90^{o}

Δ P Q R

P R^{2} = P Q^{2} + Q R^{2}

∠ Q

△ P Q R

Q R^{2} = P Q^{2} + P R^{2}

∠ P

△ P Q R, Q M

P R

P R^{2} - P Q^{2} = Q R^{2}

Q M^{2} = P M \times M R

Angles Q and R of a ΔPQR are 25° and 65°.

Write which of the following is true:

(i) PQ² + QR²= RP²

(ii) PQ² + RP²= QR²

(iii) RP² + QR²= PQ²

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