Question

In the given (V-T) diagram, what is the relation between the pressures $P_1$ and $P_2$?

• A. Cannot be predicted
• B. $P_2=P_1$
• C. $P_2>P_1$
• D. $P_2<P_1$

Answer 1

The correct option is D $P_2<P_1$

For the given curve, $\text{slope}=\frac{V}{T}$

From ideal gas relation,

$PV=nRT\Rightarrow \frac{V}{T}=\frac{nR}{P}$

$\Rightarrow \frac{V}{T}\propto \frac{1}{P}$

$\Rightarrow \text{slope}\propto \frac{1}{P}$

As ${\theta }_2>{\theta }_1$

$\therefore P_2<P_1$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(D\right)$ is the correct answer.