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Byju's Answer
Standard XII
Physics
Average Velocity in 2D Motion
In the given ...
Question
In the given v-t graph the distance traveled by the body in 5 seconds will be
A
100 m
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B
80 m
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C
40 m
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D
20 m
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Solution
The correct option is
B
80 m
Magnitude of area under the
v
−
t
graph gives the distance travelled by the body.
For
0
≤
t
≤
4
s
:
Displacement
S
1
=
Area
=
1
2
×
(
20
+
40
)
×
2
+
1
2
×
(
1
+
2
)
×
20
=
90
m
For
4
≤
t
≤
5
s
:
Displacement
S
2
=
Area
=
1
2
×
1
×
20
=
10
m
Total distance
d
=
S
1
+
S
2
=
90
+
10
=
100
m
Option A is correct.
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