Question

In the graph shown below, variation of angular speed with respect to time is given. The number of revolutions completed during the entire motion is

• A. 3600
• B. 1200
• C. 2400
• D. 1600

Answer 1

The correct option is C 2400

Total no. of revolutions = Area under the graph during entire motion
= Area of trapezium $OABC$
$=\frac{1}{2}\times (AB+OC)\times 600$
$=\frac{1}{2}\times 8\times 600=2400\text{revolutions}$