Question

In the Hall process, aluminium is produced by the electrolysis of molten $A{l}_2{O}_3$. How many seconds would it take to produce enough aluminium by the Hall process to make a case of $24$ cans of aluminium soft-drink, if each can uses $5.0g$ of $Al$, a current of $9650$ amp is employed, and the current efficiency of the cell is $90.0\text{\%}$?

• A. $203.2$
• B. $148.14$
• C. $333$
• D. $6.17$

Answer 1

Answer: (B)

$148.14$

No. of equivalent of aluminium , $\frac{W}{E}=\frac{I\times n\times t}{96500}$
$\frac{24\times 5}{27}\times 3=\frac{9650\times 0.9\times t}{96500}$
$t=148.14sec$