Question

In the HCl molecule, the separation between the nuclei of hydrogen and chlorine atoms is $1.27A^o$.If the mass of a chlorine atom is $35.5$ times that of a hydrogen atom, the centre of mass of the HCl molecucle is at a distance of

• A. $\frac{35.5\times {1.27}^0}{36.5}A$ from the hydrogen atom
• B. $\frac{35.5\times {1.27}^0}{36.5}A$ from the chlorine atom
• C. $\frac{{1.27}^0}{36.5}A$A from the hydrogen atom
• D. $\frac{{1.27}^0}{36.5}A$ from the chlorine atom

Answer 1

The correct option is A $\frac{35.5\times {1.27}^0}{36.5}A$ from the hydrogen atom