Question

In the Hoffmann-Bromamide rearrangement, intermediate compounds are:

• A. $R-\mathrm{CONHBr}$
• B. $\left(R-\mathrm{CO}-\stackrel{}{\stackrel{-}{N}-\mathrm{Br}}\right]\stackrel{+}{Na}$
• C. $R-N=C=O$
• D. All of these

Answer 1

The correct option is D All of these