Question

In the hydroboration - oxidation reaction of propene with diborane, $H_2{O}_2$ and NaOH, the organic compound formed is:

• A. $C{H}_{3}C{H}_{2}OH$
• B. $C{H}_{3}CH\left(OH\right)C{H}_3$
• C. $C{H}_{3}C{H}_{2}C{H}_{2}OH$
• D. $(C{H}_3{)}_{3}COH$

Answer 1

The correct option is C $C{H}_{3}C{H}_{2}C{H}_{2}OH$

The hydroboration oxidation reaction is shown in the above reaction that converts an alkene into neutral alcohol by the net addition of water across the double bond.

The hydrogen and hydroxyl groups are added in a syn addition leading to cis stereochemistry. Hydroboration oxidation is an anti-markovnikov reaction, with the hydroxyl group attaching to the less-substituted carbon. In the hydroboration - oxidation reaction of propene the organic compound formed is $C{H}_{3}C{H}_{2}C{H}_{2}OH$.