Question

In the hydrolytic equilibrium;
$B^{+}+H_{2}O\rightleftharpoons BOH+H^{+}$
$K_b=1\times {10}^{-5}$. The hydrolysis constant is:

• A. ${10}^{-5}$
• B. ${10}^{-19}$
• C. ${10}^{-10}$
• D. ${10}^{-9}$

Answer 1

The correct option is D ${10}^{-9}$

In equilibrium, the reaction wiill be

$B^{+}+H_{2}O\rightleftharpoons BOH+H^{+}$
Given:

$K_b=1\times {10}^{-5}$.

The hydrolysis constant for trong acid and weak base is given by

$K_h=\frac{K_w}{K_b}=\frac{{10}^{-14}}{{10}^{-5}}={10}^{-9}$